Write a function that accepts a string and returns 1 if the string is palindrome else 0 if string is not a palindrome without using any built in functions.
#include<stdio.h>
int palindrome(char str[10])
{
int i, j;
i=0;
while(str[i]!='\0')
{
i++;
}
for(j=i-1, i=0; j>=0; j--,i++)
{
if(str[i] != str[j])
return 0;
}
return 1;
}
void main()
{
char
str[10];
int p;
printf("\nEnter a string: ");
gets(str);
p=palindrome(str);
if(p)
printf("\nString is palindrome");
else
printf("\nString is not
palindrome");
}
Output:
Enter a string: abcde
String is not palindrome
Enter a string: abcba
String is palindrome
Method 2:
Method 2:
#include <stdio.h>
int main()
{
char string[20];
int i, length;
int flag = 0;
printf("Enter a string:");
scanf("%s", string);
length=0;
while(string[length]!='\0')
length++;
for(i=0;i < length ;i++)
{
if(string[i] != string[length - i - 1])
{
flag = 1;
break;
}
}
if (flag)
printf("\nstring is not a
palindrome");
else
printf("\nstring is a palindrome");
}